The conditional probability is given by:
![P(B|A)=(P(A\cap B))/(P(A))](https://img.qammunity.org/2023/formulas/mathematics/high-school/2yz3mak66i9b8gar6z4tbly9pu8v8xo6ao.png)
Let A be the event "the student is male" and B the event "First class is humanities".
The probability of A is:
![P(A)=(215)/(380)](https://img.qammunity.org/2023/formulas/mathematics/college/k8fh9l0haa56kmbxsby11fjn1sehwmdpu9.png)
The probability of event A and B is:
![P(A\cap B)=(50)/(380)](https://img.qammunity.org/2023/formulas/mathematics/college/m0296b6gtvnk4t7c0dkj1f7dc3wmyiidca.png)
Therefore the conditional probability is:
![P(B|A)=((50)/(380))/((215)/(380))=(50)/(215)=(10)/(43)](https://img.qammunity.org/2023/formulas/mathematics/college/uandr9v942ojivds14ju9tamsihuijz7hv.png)
Therefore the probability we are looking for is 10/43