Question

How do a i solve this problem? Hint: 1. Draw the forces - cart: weight downwards, normal force upwards and tension to the rightblock: weight downwards and tension upwards2. The combined mass is equal to the two masses (kgs) added together3. The tensions cancel, as do the weight and normal force of the cart, so the net force will equal the weight of the block.4. Calculate the acceleration using a = Fnet / m5. The tension can be calculated on the block with T = W - ma (since the block with accelerate downwards) or to the cart with T = ma (because no force opposes the tension).

Answer 1

A force diagram of the given system is shown below:

where,

N: normal force on cart

fg1: weight of the cart = (9 kg)(9.8m/s^2) = 88.2N

fg2: weight of the hanging mass = (2kg)(9.8m/s^2) = 19.6N

T: tension in the cable.

Based on the previous diagram and the given information, you can conclude:

Three forces are acting on the cart.

Two forces are acting on the hanging mass.

The forces are unbalanced due to the net force of the system.

The mass of the system is the sum of the given masses.

mass of the system = 9kg + 2kg = 11 kg

The net force is equal to the weight of the hanging mass:

Fnet = fg2 = 19.6N

The acceleration of the system is:

a = Fnet/m = 19.6N/(11kg) = 1.78m/s^2

After release the cart moves rightward (to the right) due to the weight of 2kg mass.

The tension is calculated by taking into account the sum of forces on the cart:

T = m1*a = (9kg)*(1.78m/s^2) = 16.02N