3 lbs of coffee
1) We can solve this problem, by setting an equation at first:
![66.54=90-7.82x](https://img.qammunity.org/2023/formulas/mathematics/college/dwb4qnxogkhkjms9wz6ovtrsj2dgwhk64c.png)
Note that, in this equation: 90 is the initial value, and x is the number of pounds of coffee. And also, the more Ann buys the less money she gets that's why the sign of 7.82 is negative.
2) Let's solve it for x:
![\begin{gathered} 66.54=90-7.82x \\ \\ 90-7.82x=66.54\:\:\:Let^(\prime)s\:work\:with\:integer\:numbers\:multiplying\:by\:100 \\ \\ 90\cdot \:100-7.82x\cdot \:100=66.54\cdot \:100 \\ \\ 9000-782x=6654 \\ \\ 9000-782x-9000=6654-9000 \\ \\ -782x=-2346 \\ \\ (-782x)/(-782)=(-2346)/(-782) \\ \\ x=3 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1ovxjugztqd97uhqvnqba2mbtqg5lnnbl2.png)
Thus, Ann bought 3 lbs of coffee