Question

What is the factored form of 1,458x ^3 - 2

Answer 1

Factorize

1,458x^3 - 2

2(729)x ^3-2 = 2 (729x ^3 -1)

Then use the next factoize form :

(ax ^3 - y^3) = (ax-y) (ax^2+axy + y^2)

where (a^3x ^3 - y^3) = (729x ^3 -1)

a^3 =729

a= 9

Using the form

(729x ^3 -1) = (9x-1) (9^2x^2+9x+1)

9^2 = 81

(9x-1) (9^2 x^2+9x+1) = (9x-1) (81 x^2+9x+1)

The whole exprresion is 2(9x-1) (81 x^2+9x+1)

The answer is the option A