Question

Need help with these parts. both parts use the same table

Answer 1

Given:

`f(x)=h(2x)`

And the values in the table.

Required:

The equation of a normal line to f at x=3.

Step-by-step explanation:

The equation of the line that passes through from point (x,y) and has slope m

is given by the formula

`y-y_1=m(x-x_1)`

From the table at x=3, f(x)=h(2x)

that is f(3)= h(6)=9

And the slope from the table at x=3 is 1/2.

Now the equation of the line is:

`\begin{gathered} y-9=(1)/(2)(x-3) \\ 2(y-9)=(x-3) \\ 2y-18=x-3 \\ x-2y=-15 \end{gathered}`

Final answer:

Thus the equation of the normal line is

`x-2y+15=0`