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at 3:00 am the temperature was -8 degrees.By early evening, the temperature rose 25 degrees at late day the temperature dropped 5 degrees. What was the late day temperature?

User Snakile
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According to the problem:

• At 3:00 am the temperature was -8°.

,

• Then, it rose 25 degrees. ,This implies a sum.

,

• At last, it dropped 5 degrees. ,This implies a subtraction.

Remember that "rising" shows a positive direction and "dropping" shows a negative direction. Following this rule, we can form the following expression


T=-8+25-5

There you can observe that the initial temperature (-8) increased (+)25, and then decreased (-)5.

Therefore, the temperature for the late day is


T=12

User Nils Guillermin
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