According to the problem:
• At 3:00 am the temperature was -8°.
,
• Then, it rose 25 degrees. ,This implies a sum.
,
• At last, it dropped 5 degrees. ,This implies a subtraction.
Remember that "rising" shows a positive direction and "dropping" shows a negative direction. Following this rule, we can form the following expression

There you can observe that the initial temperature (-8) increased (+)25, and then decreased (-)5.
Therefore, the temperature for the late day is
