Question

Y = 4 sin(18 t - 10 x). Velocity of propagation of the wave is

Answer 1

Given data:

* The equation of the wave is,

`y=4\sin (18t-10x)`

Solution:

From the equation of the wave, the angular velocity and the value of propagation constant is,

`\begin{gathered} \text{angular velocity }\omega=18\text{ radian/second} \\ \text{Propagation constant k =10 radian/meter} \end{gathered}`

The value of the velocity of propagation is,

`\begin{gathered} v=(18)/(10) \\ v=1.8\text{ m/s} \end{gathered}`

Thus, the velocity of the propagation of wave is 1.8 m/s.