Given:
ABCD is isosceles trapezoid.
AC=3x-4 and BD=x+8 are the diagonals of the given trapezoid.
Required:
We need to find the value of x and the length of AC.
Step-by-step explanation:
Recall that the diagonals of an isosceles trapezoid have the same length

Substitute AC=3x-4 and BD=x+8 in the equation to find the value of x.

Add 4 to both sides of the equation.


Subtract x from both sides of the equation.


Divide both sides of the equation by 2.


We get x =6 and substitute x =6 in the equation AC=3x-4 to find the length of AC.


Final answer:

