Question

In a standard (x,y) coordinate plane, what is the distance between the origin and point (5,-12)

Answer 1

We are given two points from the question

(0, 0) because the line passes through the origin and (5, -12)

From the given points

x1 = 0, y1 = 0, x2 = 5, and y2 = -12

`\begin{gathered} Dis\tan ce\text{ = }\sqrt[]{(x1-x2)^2+(y1-y2)^2} \\ \text{Distance = }\sqrt[]{(0-5)^2+(0-(-12)\rbrack^2} \\ =\text{ }\sqrt[]{(-5)^2+(12)^2} \\ =\text{ }\sqrt[]{25\text{ + 144}} \\ =\text{ }\sqrt[]{169} \\ =\text{ 13} \end{gathered}`

The distance between the origin and point (5, -12) is 13

The answer is 13, OPTION D