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Let's say you have two like segments, AB and CD which bisects each other at point E. Explain why AC = DB

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Based on the given information, we can represent the problem as a diagram.

Notice that segments AC and DB form triangles, Where CE = ED and AE = EB. Also, angles AEC and BED are equal by the vertical angles theorem.

Therefore, by angle-side-angle postulate, triangles AEC and BED are congruent. From that congruence is deducted that AC = DB.

Let's say you have two like segments, AB and CD which bisects each other at point-example-1
User Itsjavi
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