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Sovle for x round to the nearest tenth 19 32 g h

Sovle for x round to the nearest tenth 19 32 g h-example-1

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SOLUTION

The figure below is a right-angled triangle. To find angle x, we will apply the trig-ratio, that is SOHCAHTOA

Which is


\begin{gathered} \text{SOH sin}\theta=\frac{opposite}{\text{hypotenuse}} \\ \text{CAH cos}\theta=\frac{adjacent}{\text{hypotenuse}} \\ \text{TOA tan}\theta=\frac{opposite\text{ }}{\text{adjacent }} \end{gathered}

But we will make use of SOH, we have


\begin{gathered} \text{ }\sin x=\frac{opposite}{\text{hypotenuse}} \\ \text{ }\sin x=(19)/(32) \\ \sin x=0.59375 \\ x=\sin ^(-1)0.59375 \\ x=36.42357 \end{gathered}

Hence, the answer is 36.4 to the nearest tenth

User Amrith Raj Herle
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