Given:
The frequency emitted by the source, f_s=900 GHz
The observed frequency, f=820 GHz
To find:
The speed of the source and the direction of motion of the source.
Step-by-step explanation:
The change in the frequency is given by,
![\Delta f=f_s-f](https://img.qammunity.org/2023/formulas/physics/college/6qwzutwvk2780ckz9nohwtojkcbuqcincs.png)
On substituting the known values,
![\begin{gathered} \Delta f=900\text{ GHz}-820\text{ GHz} \\ =80\text{ GHz} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/9gk5i77tfiwc4y3mana3ll5necarce0eay.png)
Thus the change in the frequency is positive. That is the frequency is decreasing. This is called a redshift and the star is moving away from the earth.
The speed of the source is given by the equation,
![f=f_s*(c)/(c+v)](https://img.qammunity.org/2023/formulas/physics/college/uomqtyavi9silcf2tvjajsfroy5fypowyj.png)
Where c is the speed of light and v is the speed of the source.
On substituting the known values,
![\begin{gathered} 820*10^9=900*10^9*(3*10^8)/(3*10^8+v) \\ \implies v=(900*10^9*3*10^8)/(820*10^9)-3*10^8 \\ =29.3*10^6\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/nk5hcdtpgmv7ktnxiw0uloc51l3x7qfmtk.png)
Final answer:
The velocity of the star is 29.3×10⁶ m/s
And the star is moving away from the earth.