Area A= 10 cm2
Area B= ?
Isosceles triangle
12/4 = B/b
Area A = b x h = (b/2) x √4^2 - (b/2)^2
height h= √256 -
25= (b/2)^2• (16 - (b/2)^2)
find b/2= 1.75
Therefore b= 3.5
then now find B, bigger base
B = 3•b = 3•3.5= 10.5
Area B = BxH
H = √ 116= 10.8
Then answer is
Area B = 2 x 10.5x 10.8= 226.8 cm2