Given: Triangles ABC and DEF are given such that
![\begin{gathered} \angle A=111\degree \\ \angle B=52\degree \\ \angle D=111\degree \\ \angle F=17\degree \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/du8yceyfn0mj0l29wzdrnv3u1me2bqxb2z.png)
Required: To determine the similarity of the given triangles.
Explanation: Two triangles are said to be similar if their corresponding angles are equal.
In triangle ABC, we have-
![\angle A+\angle B+\angle C=180\degree\text{ ...}(\text{Angle sum property})](https://img.qammunity.org/2023/formulas/mathematics/college/9gr1c82xamyntc9im9vmtod428yrczqiv0.png)
Thus,
![\begin{gathered} \angle C=180\degree-111\degree-52\degree \\ \angle C=17\degree \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7rozzb53a8l4v846amtpm693aps503efzg.png)
Now, in triangles ABC and DEF, we have
![\begin{gathered} \angle A=\angle D \\ \angle C=\angle F \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/our978qkxnxttwsnt71hdz4nluh7y71eoq.png)
Therefore, by the AA rule of similarity
![\Delta ABC\approx\Delta DEF]()
Final Answer: Option C is correct.