31.5k views
1 vote
Application problem with a linear function: Finding a coordinate given two points

Application problem with a linear function: Finding a coordinate given two points-example-1

2 Answers

4 votes

The monthly cost for 81 minutes is $19.47

Using the information given , we can determine the linear equation for the graph.

The slope-intercept form of the equation is expressed as ;

  • y = bx + c ; b = slope , c = intercept

Using the pair of points; (54, 17.04) ; (86, 19.92)

The slope = (19.92 - 17.04) / (86 - 54)

slope, b = 0.09

Now we can calculate c ;

17.04 = 0.09(54) + c

17.04 = 4.86 + c

c = 12.18

The linear equation would be ;

  • y = 0.09x + 12.18

B.)

Monthly cost for 81 minutes of call ; x = 81

y = 0.09(81) + 12.18

y = 7.29 + 12.18

y = 19.47

User Gaurav P
by
8.9k points
3 votes

$19.47

1) Examining the graph, we can write two coordinate pairs the x-coordinate for the minutes and the y-coordinate for the cost. So we have (54, 17.04) and (86, 19.92) so we can find from that the rule of this function. Let's find the slope of it:


m=(y_2-y_1)/(x_2-x_1)=(19.92-17.04)/(86-54)=0.09

Note that the slope shows how steep is the line of that function.

2) Let's find the linear coefficient, where the graph intercepts the y-axis.

Writing the slope-intercept form:


\begin{gathered} y=mx+b \\ \mleft(54,17.04\mright) \\ 17.04=0.09(54)+b \\ 17.04-4.86=b \\ b=12.18 \end{gathered}

So the rule of this function is:


f(x)=0.09x+12.18

3) Now we can find out the answer, by plugging into that equation x=81


\begin{gathered} f(81)=0.09(81)+12.18 \\ f(81)=19.47 \end{gathered}

Thus, the monthly cost for 81 minutes is $19.47

User Acey
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories