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Create any line parallel to the line y= -1/3x+2

User Kvvaradha
by
4.4k points

1 Answer

2 votes


y=-(1)/(3)x

Step-by-step explanation

Step 1

if two lines are parallel, then


\text{slope}_(_1)=slope_2

So, we have


y=(-1)/(3)x+2\rightarrow y\text{ = mx+b}

Hence,


\begin{gathered} \text{slope}1=(-1)/(3) \\ \text{sloep}1=\text{ slope2,then} \\ \text{slope}_2=(-1)/(3) \end{gathered}

Step 2

according to the question , we can create any line, so we can select any point,

let

P1(0,0) and slope=-1/3


\begin{gathered} y-y_1=m(x-x_1) \\ \text{replacing} \\ y-0=-(1)/(3)(x-0) \\ y=-(1)/(3)x \end{gathered}

User Aafreen Sheikh
by
4.9k points