Answer:
For #3 the chart is basically as x in (x) and f(x) as in Y
The domain is the x
the range is the Y
Now we can do slope formula
y2-y1/ x2-x1
Pick two random points for example to make life easier here Ill do
(2,5) and (3,9)
Now plug it in
3-2=1
9-5=4
4/1
4 is the slope.
The Y intercept is consisted of
y=mx+b
Wheras y and x you just leave it alone while m is the slope and b is the y-intercept
Now in order to find the Y intercept we need the X to be 0.
So it has to be (0, y)
Now we already found out the slope which is 4/1
And the slope is also the rate of change. Using that information we can just add 4 to the y whilst adding 1 to the x.
Now we already have it set up for us.
We can start from (-1, -7)
So following the order
add 1 to x and 4 to y
(0, -3)
Now we know the y- intercept which is -3
Now plug it in all together
-3 is (b)
For number 4 you have a graph. This should be much less work. Its going on a negative slope so we already know the slope is gonna be negative. So theres 2 ways, we can go on a random point and then count the rise/ run Or we can find 2 points on the graph and then Do the slope formula. I’m gonna do the rise over run So I’m gonna start from a given point and its rise 1 and then run left since its a negative slope 5 times and it puts me to the second point.
The slope is 1/5
The y intercept, we just need to find (b) or the y intercept
So in this case where does the line first make contact with the Y axis in this case it’s on the point (0, -1)
the y intercept is -1