Answer:
y = 2x + 5
Explanation:
Slope-intercept form: y = mx + b
where:
- m is the slope
- b is the y-intercept (when x = 0)
Given: a line with a slope of 2, and y-intercept of 5
Equation: y = 2x + 5
Randomly select y-values that will help you graph the equation:
when y = -9:
-9 = 2x + 5 [subtract 5 from both sides]
-9 - 5 = 2x
-14 = 2x [divide both sides by 2]
-14 ÷ 2 = 2x ÷ 2
-7 = x
coordinate: (-7, -9)
when y = -5:
-5 = 2x + 5 [subtract 5 from both sides]
-5 - 5 = 2x
-10 = 2x [divide both sides by 2]
-10 ÷ 2 = 2x ÷ 2
-5 = x
coordinate: (-5, -5)
when y = -1:
-1 = 2x + 5 [subtract 5 from both sides]
-1 - 5 = 2x
-6 = 2x [divide both sides by 2]
-6 ÷ 2 = 2x ÷ 2
-3 = x
coordinate: (-3, -1)
when y = 3:
3 = 2x + 5 [subtract 5 from both sides]
3 - 5 = 2x
-2 = 2x [divide both sides by 2]
-2 ÷ 2 = 2x ÷ 2
-1 = x
coordinate: (-1, 3)
With these coordinates, graph them on a coordinate plane and draw a straight line through them. That should be the graph of the equation.