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Solve for x log 3x+4) = 2

User Tmarwen
by
8.5k points

1 Answer

1 vote

Step 1:

Write the equation


\log ^(3x+4)_4\text{ = 2}

Step 2:

Express the equation in exponential form


\begin{gathered} \log ^{3x+\text{ 4}}_4\text{ = 2} \\ 3x+4=4^2 \\ 3x\text{ + 4 = 16} \\ 3x\text{ = 16 - 4} \\ 3x\text{ = 12} \\ x\text{ = }(12)/(3) \\ x\text{ = 4} \end{gathered}

Final answer

x = 4

User Theus
by
8.0k points

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