Question

Who exhibits more power?A) Bob transfer 2000 J in 3 minutes.B) Carl transfers 2 J in 0.1 s.C) Alan transfers 20 J in 0.5 s.

Answer 1

Given that:

A) Energy,

`E_B=\text{ 2000 J}`

The time is

`\begin{gathered} t_B=3\text{ min} \\ =3*60\text{ s} \\ =180\text{ s} \end{gathered}`

B) Energy,

`E_C=2\text{ J}`

and time

`t_C=0.1\text{ s}`

C) Energy

`E_A=20\text{ J}`

and time

`t_A=0.5\text{ s}`

We have to find the power for all three cases.

The formula to calculate power is

`P=(E)/(t)`

The power transferred by Bob will be

`\begin{gathered} P_B=(E_B)/(t_B) \\ =(2000)/(180) \\ =11.11\text{ W} \end{gathered}`

The power transferred by Carl will be

`\begin{gathered} P_C=(E_C)/(t_C) \\ =(2)/(0.1) \\ =20\text{ W} \end{gathered}`

The power transferred by Alan will be

`\begin{gathered} P_A=(E_A)/(t_A) \\ =(20)/(0.5) \\ =40\text{ W} \end{gathered}`

Thus, Alan exhibits more power.