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Determine the equation of the line that passes through the point (1/7,1) and is parallel to the line −4y−3x=−3

User Jpellat
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SOLUTIONS

The parallel line will be of form


m_1=m_2

the equation of the line that passes through the point (1/7,1) and is parallel to the line −4y−3x=−3


\begin{gathered} -4y-3x=-3 \\ -4y=3x-3 \\ y=(3x)/(-4)-(3)/(-4) \\ y=-(3)/(4)x+(3)/(4) \\ y=mx+c \\ m_1=-(3)/(4) \end{gathered}

The equation of the line parallel to point(1/7 , 1)


\begin{gathered} y-y_1=m(x-x_1) \\ x_1=(1)/(7),y_1=1 \\ y-1=-(3)/(4)(x-(1)/(7)) \\ y-1=-(3)/(4)x+(3)/(28) \\ y=-(3)/(4)x+(3)/(28)+1 \\ multiply\text{ through by 28} \\ 28y=-21x+3+28 \\ 28y=-21x+31 \end{gathered}

User Derek Nguyen
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