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I just need to make sure 1-9 are correct so if you could confirm please.9 b)

I just need to make sure 1-9 are correct so if you could confirm please.9 b)-example-1
User BlackShift
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1 Answer

6 votes

Given:


2x^2+3x+9=0

To find:

The roots.

Step-by-step explanation:

Here,


\begin{gathered} a=2 \\ b=3 \\ c=9 \end{gathered}

Using the quadratic formula,


x=(-b\pm√(b^2-4ac))/(2a)

On substitution we get,


\begin{gathered} x=(-3\pm√((3)^2-4(2)(9)))/(2(2)) \\ =(-3\pm√(9-72))/(4) \\ =(-3\pm√(-63))/(4) \\ =(-3\pm3i√(7))/(4) \end{gathered}

Therefore, the solutions are,


x=(-3+3\imaginaryI√(7))/(4),x=(-3-3\imaginaryI√(7))/(4)

Final answer:

The solutions are,


x=(-3+3\imaginaryI√(7))/(4),x=(-3-3\imaginaryI√(7))/(4)

User Jessica Lingmn
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