We need to identify one point that belongs to the function besides (4,0). For that, we have to choose one "x" coordinate and determine the value of y. Let's choose x= 6. The value of y is calculated below:
![\begin{gathered} f(6)=\sqrt[3]{6-4} \\ f(6)=\sqrt[3]{2}=1.26 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/z59kox3mipa37n8986kavbh88rnzsjdhqk.png)
The point we need to find is (6, 1.26). The resulting graph is: