Answer:
The coordinates of D' and F are;
![\begin{gathered} D^(\prime)(0,-1) \\ F(9,10) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/j1pee2c8a5m8zcnnbra56r1fwyfllvfn74.png)
Step-by-step explanation:
Given the triangles DEF mapped onto D'E'F'.
Given then the coordinate;
![\begin{gathered} D(5,2) \\ E(7,-3) \\ E^(\prime)(2,-6) \\ F^(\prime)(4,7) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/dei1qfnr9wrtutucz1tgcxuio48rvh4esj.png)
Let us find the translation used to map triangle DEF to D'E'F'.
![\begin{gathered} E(7,-3)\rightarrow E^(\prime)(2,-6) \\ (x,y)\rightarrow(x+(2-7),y+(-6--3)) \\ (x,y)\rightarrow(x-5,y-3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/f6sj5sebjcppbuv4at7ewxzkncjvs4sz0z.png)
Applying the translation to point D;
![\begin{gathered} (x,y)\rightarrow(x-5,y-3) \\ D(5,2)\rightarrow D^(\prime)(5-5,2-3) \\ D(5,2)\rightarrow D^(\prime)(0,-1) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/mwqayb24oi0oidn60cwemdccawbeazk14n.png)
Also to get F;
![\begin{gathered} F(x,y)\rightarrow F^(\prime)(x-5,y-3) \\ F^(\prime)(4,7) \\ x-5=4 \\ x=4+5 \\ x=9 \\ y-3=7 \\ y=7+3 \\ y=10 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/o37csristiltdn23vsfjjw94ev6s8ost0m.png)
The coordinate of point F is;
![F(9,10)](https://img.qammunity.org/2023/formulas/mathematics/high-school/wf0h7gt8qibhsqyopkdlq8f80uke66x5h5.png)
Therefore, the coordinates of D' and F are;
![\begin{gathered} D^(\prime)(0,-1) \\ F(9,10) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/j1pee2c8a5m8zcnnbra56r1fwyfllvfn74.png)