In order to simplify this expression, first let's put the denominator of the first fraction in the factored form:

To do so, let's find the zeros of the polynomial using the quadratic formula:
![\begin{gathered} x^2+12x+35=0 \\ a=1,b=12,c=35 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_1=\frac{-12+\sqrt[]{144-140}}{2}=(-12+2)/(2)=-5 \\ x_2=(-12-2)/(2)=-7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/e53255iqjo5kyklnhco82fqsr8jxaur8fv.png)
So we have:

Now, let's simplify the expression by inverting the division (turning it into a product) and canceling the like terms:

The right side of the expression is correct, therefore the answer is TRUE.