Question

An organ pipe (open at both ends) is 1.23 m long. If the speed of sound is 340 m/s, what is its fundamental frequency?

Answer 1

The fundamental frequency in this case will be given by:

`f_1=(v_s)/(2l)`

Where:

`\begin{gathered} _{\text{ }}v_s=Speed_{\text{ }}of_{\text{ }}sound \\ _{\text{ }}l=Length \end{gathered}`

Therefore:

`\begin{gathered} f_1=(340)/(2\cdot1.23) \\ f_1=138.211Hz \end{gathered}`

Answer:

138.211 Hz