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If x > 2, find lx-2l

Help pleaseee

If x > 2, find lx-2l Help pleaseee-example-1
User Junlin
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1 Answer

13 votes

Answer: x-2

Step-by-step explanation:

If x > 2, then x-2 > 0 after subtracting 2 from both sides.

Since x-2 is always positive when x > 2, this means the absolute value bars around the x-2 aren't needed. The results of |x-2| and x-2 are perfectly identical.

For example, if we tried something like x = 5, then

  • x-2 = 5-2 = 3
  • |x-2| = |5-2| = |3| = 3

Both outcomes are 3. I'll let you try other x inputs.

So because |x-2| and x-2 are identical, this means |x-2| = x-2 for all x > 2.

In short, we just erase the absolute value bars.

User Di Ye
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