Question

Find the area of a rhombus whose has a perimeter of 20 m and one diagonal that measures 6 m.

Answer 1

`A\text{ : 24 m}^2`

Step-by-step explanation:

Here, we want to get the area of the Rhombus

Mathematically, we have that as:

`A\text{ = }(1)/(4)d√(P^2-4d^2)`

where:

d is the length of the diagonal, given as 6m

P is the perimeter of the Rhombus, given as 20 m

Substituting the values, we have it that:

`\begin{gathered} A\text{ = }(1)/(4)6√(20^2-4*6^2) \\ \\ A\text{ = }(1)/(4)6√(400-144) \\ \\ A\text{ = }(1)/(4)*6*16\text{ = 24 m}^2 \end{gathered}`