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Andrey Pokrovskiy · Answer 1 · 2023-01-22T02:29:45+0000

First, let's calculate the electric force, using the formula below:

$\begin{gathered} F_e=(KQq)/(d^2)\\ \\ F_e=(9\cdot10^9\cdot(22.78\cdot10^(-6))^2)/(4.22^2)\\ \\ F_e=262.26\cdot10^(-3)=0.26226\text{ N} \end{gathered}$

Now, let's use the second law of Newton to find the acceleration:

$\begin{gathered} F=m\cdot a\\ \\ 0.26226=1.21\cdot a\\ \\ a=(0.26226)/(1.21)\\ \\ a=0.217\text{ m/s^^b2} \end{gathered}$

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