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41 votes
41 votes
Solve the equations.


\sqrt{x^(2) } =14

\sqrt{x^(2) } =17

\sqrt{y^(2) } =5

User Timop
by
3.0k points

1 Answer

12 votes
12 votes

Answer:


x=\pm14\\x=\pm17\\y=\pm5

Explanation:

Generally, equations in the form
√(x^2)=c where
c is some constant, would have
x=\pm c as its solution.

This is because the square of a number is always positive regardless of the sign of
x.

User Crocobag
by
3.2k points