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Slope = 3, passing through (-4,7)

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The slope of line is m = 3.

The line passing through point (-4,7).

The general equation for point-slope form of equation is,


y-y_1=m(x-x_1)

Determine the equation for m = 3 and point (-4,7).


y-7=3(x+4)

Thus, point-slope form of equation is y - 7 = 3(x + 4).

Simplify the point-slope form of equatio to ontain the slope-intercept form of equation.


\begin{gathered} y-7=3(x+4) \\ y=3x+12+7 \\ y=3x+19 \end{gathered}

Thus, equation of line in slope-intercept form is y = 3x + 19.

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