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Determine how many real solutions tbe equation y=2x^2-4+10 has by using the discriminant

User Kaye
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Consider the given quadratic equation,


y=2x^2-4x+10

Compare with the standard form,


y=ax^2+bx+c

It is obtained that,


\begin{gathered} a=2 \\ b=-4 \\ c=10 \end{gathered}

The discriminant is calculated as,


\begin{gathered} D=b^2-4ac \\ D=(-4)^2-4(2)(10) \\ D=16-80 \\ D=-64 \end{gathered}

Since the value of the discriminant is less than zero, both the solutions of the given quadratic equation are imaginary.

Therefore, there is no real solutions of the quadratic equation.

User Navarasu
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