Question

A student measures the molar solubility of silver sulfite in a water solution to be 1.53x10-5M. Based on her data , the solubility product constant for this compound is

Answer 1

Step-by-step explanation

Given that:

`\text{ The molar solubility of silver sulfide is 1.53 x 10}^(-5)`

To find the solubility constant product for the compound, follow the steps below

Step 1: Write the ionic equation for silver sulfite

`Ag_2SO_3\rightarrow\text{ 2Ag}^+\text{ + SO}_3^(2-)`

From the above reaction, the silver sulfite split into silver ion and sulfite ion