a)I=2.4 A
b)I=0.3 A
c)1.5 ohms
Step-by-step explanationOhm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.it is represented in the equations

so
Step 1
a) given

replace in the proper formula, so

so
a)I=2.4 A
Step 2
i)let

replace

so
b)I=0.3 A
Step 3
finally, to find the resistenace, let

replace in the proper formula

so
c)1.5 ohms
I hope this helps you