Given:
A swimming pool is in the form of a semicircular-sided figure
Required:
What is the area of the 3 ft wide surrounding the pool?
Step-by-step explanation:
We will find area as:
![\begin{gathered} A=\text{ Area of semicircle including side walk }-\text{ Area of semicircle without } \\ \text{side walk} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/69h543an2p7mjyr8gfuosbylayz5ujbl20.png)
Now, radius for smaller semicircle is 5 ft and radius for larger semicircle (5 + 3 = 8)
So,
![\begin{gathered} A=((3.14*8^2)/(2))-((3.14*5^2)/(2)) \\ A=100.48-39.25 \\ A=61.23ft^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qy24eqw67c7zmiyi382dir3sv83dzxhf3j.png)
If we take walk on both sides, we will multiply it with 2
A = 2*61.23
A = 122.46 ft square
Now, we have one side of bigger rectangle is 10 + 3 + 3 = 16 ft
So,
![\begin{gathered} A\text{ = area of rectangle - area of square} \\ A=(16*10)-10^2 \\ A=60ft^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nn6rgct3cddjeny7pzmv9775a68768qy4t.png)
Finally,
![\begin{gathered} A=122.46+60 \\ A=182.46ft^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mhee9zy927zdutx2rtwwwz7j9zbnq5wvab.png)
Answer:
Hence, above is the answer.