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Write the equation in standard form for the circle with center (0,3) and radius 2/14

Write the equation in standard form for the circle with center (0,3) and radius 2/14-example-1
User Arucker
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1 Answer

3 votes

Given:


\text{The center, \lparen h,k\rparen =\lparen0,3\rparen.}
The\text{ radius, r=2}√(14).

Required:

We need to find the equation in standard form for the circle.

Step-by-step explanation:

Consider the equation in standard form for the circle.


(x-h)^2+(y-k)^2=r^2
\text{ Substitute h =0, k=3 and r =2}√(14)\text{ in the formula.}


(x-0)^2+(y-3)^2=(2√(14))^2


(x-0)^2+(y-3)^2=2(√(14))^2
Use\text{ \lparen}√(14))^2=14.
x^2+(y-3)^2=2^2*14


x^2+(y-3)^2=56

Final Answer:

The equation in standard form for the circle is,


x^2+(y-3)^2=56.

User Gio
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