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C. O 32.44 m/sD. O 24.45 m/sE. O 3.293 m/s6. A certain spring extends by 0.4 m when an objectof mass 0.9 kg hangs from it. Calculatethe Hook's constant of the spring. (1 point)A. O13.416 N/mB. O 33.766 N/mC. 38.169 N/mD. O 22.05 N/mE. O8.241 N/m

C. O 32.44 m/sD. O 24.45 m/sE. O 3.293 m/s6. A certain spring extends by 0.4 m when-example-1
User AFgone
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1 Answer

3 votes

Given,

The mass of the object is


m=0.9\text{ kg}

The length of the spring is


x=0.4\text{ m}

To find: Calculate the Hook's constant.

Solution:

Hook's law is given as


F=kx

Now,


\begin{gathered} k=(mg)/(x) \\ k=(0.9*9.8)/(0.4) \\ k=22.05\text{ N/m} \end{gathered}

Hence, the given option (d) is correct.

User Miggz
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