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In AQRS, the measure of ZS=90°, QR = 71 feet, and SQ = 50 feet. Find the measure of ZR to the nearest degree.

User Orique
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1 Answer

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we get that:


\sin x=(11)/(32)\rightarrow x=\arcsin (11)/(32)=20.10^(\circ)\approx20^(\circ)^{}

User Achilles
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