Before we graph the given equation, let's convert it to slope-intercept form first. Here are the steps.
1. Subtract 5 on both sides of the equation.
![\begin{gathered} 5+3y-5=x-5 \\ 3y=x-5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fwk8ul82vcwoq6ustsqfahvi5px76m2m18.png)
2. Next, divide both sides of the equation by 3.
![(3y)/(3)=(x)/(3)-(5)/(3)\Rightarrow y=(1)/(3)x-(5)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/a5rhoqc2kqckfw6oq5d2rs5t2cn9wj47df.png)
We have converted the equation to slope-intercept form.
The slope is 1/3 and the y-intercept is -5/3 or -1.67.
To complete the given coordinate, simply replace "x" with the given x-coordinate and solve for y in the slope-intercept form.
Let's start with (2, ?) which is x = 2.
![\begin{gathered} y=(1)/(3)(2)-(5)/(3) \\ y=(2)/(3)-(5)/(3) \\ y=-(3)/(3) \\ y=-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/q0hermm9f1hgbnu0zk2v5z21yukzrtdelg.png)
At x = 2, y = -1. Completing the first coordinate, we have (2, -1).
Next, at x = -1.
![\begin{gathered} y=(1)/(3)(-1)-(5)/(3) \\ y=(-1)/(3)-(5)/(3) \\ y=(-6)/(3) \\ y=-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/phl1zuh5ixxud9d6hky2foxb1pr1u2i9dt.png)
Completing the second coordinate, we have (-1, -2).
Lastly, at x = -4:
![\begin{gathered} y=(1)/(3)(-4)-(5)/(3) \\ y=(-4)/(3)-(5)/(3) \\ y=(-9)/(3) \\ y=-3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hf9d4ngohbs4afu0o6ezdpjaoelz00bqdh.png)
Completing the third coordinate, we have (-4, -3).
The graph of this equation is shown below: