Question

Solve for x in the equation logx(1/64) = -2.

Answer 1

Solve for x:

`log_x\left((1)/(64)\right)=-2`

Applying the definition of logarithms:

`x^(-2)=(1)/(64)`

Operating:

`(1)/(x^2)=(1)/(64)`

Applying square root:

`\begin{gathered} (1)/(x)=(1)/(8) \\ \\ \text{ Or, equivalently:} \\ \\ x=8 \end{gathered}`