Each circle corresponds to a different value of r (the first coordinate, on the left).
And each line segment emanating from the center corresponds to a different value of θ (second coordinate, on the right).
Also, we need to know that a negative value of θ corresponds to the angle 2π - θ.
Furthermore, if r is negative, we need to plot the point opposite by the center to the point (-r, θ).
So, let's begin by plotting the point
![(-5,-(7\pi)/(6))](https://img.qammunity.org/2023/formulas/mathematics/college/i54yaca3048rn5oscmaqid2q3ehk8mk3as.png)
Since the second entry is negative, it corresponds to the angle:
![2\pi-(7\pi)/(6)=(12\pi-7\pi)/(6)=(5\pi)/(6)](https://img.qammunity.org/2023/formulas/mathematics/college/w5xjhsz9vzt8r0ahzduso0vt6oj64ghlfo.png)
Also, since the first entry is negative, we need to plot the point on the circle corresponding to r = 5, but in the opposite direction of the ray corresponding to the angle 5π/6:
Now, the second point is
![(3,(3\pi)/(4))](https://img.qammunity.org/2023/formulas/mathematics/college/lkrlwpe46d86b1vtywmrpzrtc0ctxdee2b.png)
For this point, both coordinates are positive. So, we need to plot it (red point below) on the circle corresponding to r = 3, and on the ray corresponding to θ = 3π/4: