Question

Two planets orbit each other at a distance of 1.25 * 10 ^ 10 * n Planet 1 has a mass of 7.35*10^ 22 kg and planet 2 has a mass of 1.31*10^ 22 kg . What is the force acting on planet 1? And planet 2?

Answer 1

Given data

*The given distance between the planets is r = 1.25 × 10^10 m

*The mass of planet 1 is m = 7.35 × 10^22 kg

*The mass of another planet is M = 1.31 × 10^22 kg

*The value of the gravitational constant is G = 6.67 × 10^-11 m^3/kg.s^2

The formula for the gravitational force acting on planet 1 and planet 2 is given as

`\begin{gathered} F=F_1=F_2 \\ =(GmM)/(r^2) \end{gathered}`

Substitute the known values in the above expression as

`\begin{gathered} F=\frac{(6.67*10^(-11))(7.35*10^(22))(1.31*10^{22^{}})}{(1.25*10^(10))^2} \\ =4.11*10^(15)\text{ N} \end{gathered}`

Hence, the gravitational force acting between planet 1 and planet 2 is F = 4.11 × 10^15 N