Given data
*The given complete set has a mass is m = 3467 kg
*The speed of the cart with a horizontal velocity relative to the floor is v_1 = 0.02 m/s
*The speed of the librarian is v_2 = 2.40 m/s
The formula for the librarian's mass (m_l) is given by the conservation of momentum as
![mv_1=m_lv_2](https://img.qammunity.org/2023/formulas/physics/high-school/celgktehyaqvd09qeyb7vn4beu24n73gfp.png)
Substitute the known values in the above expression as
![\begin{gathered} 3467*0.02=m_l*2.40 \\ m_l=(3467*0.02)/(2.40) \\ =28.89\text{ kg} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/y3e91tsbxmkq8efy34n06g7njgz4hxgg1p.png)
Hence, the librarian's mass is m_l = 28.89 kg