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The equation: x^2+3x-4 has two solutions. The smaller is x= _____Find the smaller solution.

User Ilyar
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The given quadratic equation is:


x^2+3x-4=0

Solve by factoriztion as follows:


\begin{gathered} x^2+4x-x-4=0 \\ x(x+4)-1(x+4)=0 \\ (x+4)(x-1)=0 \\ x+4=0\text{ or x-1=0} \\ x=-4,1 \end{gathered}

So the smaller solution is x=-4.

User Kapilsdv
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