Question

We are currently learning about a new topic in algebra and I don't understand please help

Answer 1

let us put the first equation y = 6x -11 into the second equation and we get

`-2x-3(6x-11)=-7`

Simplifies the above gives

`-2x-18x+33=-7`
`-20x=-40`
`\textcolor{#FF7968}{\therefore x=2.}`

Using this value of x in y = 6x - 11 gives

`y=6(2)-11`
`\textcolor{#FF7968}{\therefore y=1.}`

Finally, we put in x = 2 and y = 1 into the last equation and solve for z.

`3(2)-5(1)+6z=25`
`6z=24`
`\textcolor{#FF7968}{\therefore z=4.}`

Hence, our solution is (x, y, z) = (2, 1, 4).