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Given : Load = 50 kgf Load arm = 30 cm Effort arm = 1.20m What will be the Mechanical advantage ? (equation must be shown)

Given : Load = 50 kgf Load arm = 30 cm Effort arm = 1.20m What will be the Mechanical-example-1
User Pilou
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Givens.

• Load = 50 kgf

,

• Load arm = 30 cm

,

• Effort arm = 1.20m

The mechanical advantage formula is


MA=(F_(out))/(F_i)

It's the ratio between the forces involved.


MA=(Effort)/(Load)

However, we can use the distances to find the same ratio about the mechanical advantage.


MA=\frac{120\operatorname{cm}}{30\operatorname{cm}}

Observe that we use 1.20 meters as centimeters because we need both distances with the same units.


MA=(120)/(30)=4

Therefore, the mechanical effort is about 4, that is, the point where the effort is made represents 4 times the load.

User Utaco
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