Answer
The x-intercepts are:
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The y-intercept is:
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SOLUTION
Problem Statement
The question tells us to graph the following function

Step-by-step explanation
1. Create Table of Values:
To plot the function, we need to create a table of values for x and f(x). We shall choose x-values ranging from -3 to 4, with steps of 0.5
The corresponding y-values, can be gotten by substituting the x-values into the function as shown below:

The calculation gives a brief summary of how the values of table we shall use to plot the graph is obtained.
The Table of values is given below:
2. Plotting the Graph:
After getting the table of values, we simply need to locate each point on the graph and join them using a curve.
The points plotted on the graph are shown below:
After plotting the points as shown in the figure above, we just simply join the points via a curve.
The curve is shown below:
Thus, we can read off the x-intercepts and y-intercept from the graph given above.
x-intercepts are where the graph crosses the x-axis.
y-intercept is where the graph crosses the y-axis
The x and y intercepts are shown below:
Thus, the x-intercepts are:

The y-intercept is:
