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28 votes
28 votes
1. What is the vertex for the following quadratic function, y = 2x^2 - 4x + 5?

A). (1,3)
B). (3, 1)
C) (0,5)
D). (2,5)

User Ankur Khandelwal
by
2.8k points

1 Answer

9 votes
9 votes

Answer:

A

Explanation:

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = -
(b)/(2a)

y = 2x² - 4x + 5 ← is in standard form

with a = 2 and b = - 4 , then


x_(vertex) = -
(-4)/(4) = 1

Substitute x = 1 into the equation for corresponding value of y

y = 2(1)² - 4(1) + 5 = 2 - 4 + 5 = 3

vertex = (1, 3 ) → A

User MW Frost
by
3.5k points