Given:
The system of the equation is,

Draw the lines on the graph, the point at which the lines intersects. That point will be the solution of the system.
The points on the line 2x+5y=0 are,

And the points on the line x+6y=14

The graph of the lines is,
As the point of intersection is ( -10,4).
The solution of the given system of equation is x = -10, y = 4.