Given:
EG = 2.8, OE = 3.5,
Required: OF
To solve this problem, we need to apply this rule:
The tangent is always perpendicular to the radius drawn to the point of tangency.
Hence, we can draw:
Let the length of OF be r
Using Pythagoras theorem, we can solve for r
![\begin{gathered} hypothenuse^2\text{ = opposite}^2\text{ + adjacent}^2 \\ 3.5^2\text{ = r}^2+\text{ 2.8}^2 \\ r^2\text{ = 4.41} \\ r\text{ = 2.1} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4oed3t2onsuiifoq6i5s0k2204b9w0krkz.png)
Hence, the length of OF is 2.1